解答下列问题:
(1)把(a-b)2看成一个整体,合并3(a-b)2-7(a-b)2+2(a-b)2的结果是 ;
(2)已知a+b=5(a-b),代数式
;
(3)已知:xy+x=-6,y-xy=2,求2[x+(xy-y)2]-3[(xy-y)2-y]-xy的值.
答案
(1);
(2);
(3)-10.

(1)原式=-2(a-b)2;
(2)因为a+b=5(a-b),
所以,原式=
=+20
=;
(3)因为xy+x=-6,y-xy=2,
所以xy+x+y-xy=x+y=-4
所以,原式=2(x+4)-3(4-y)-xy
=2x+8-12+3y-xy
=2x+3y-xy-4
=2x+2y+y-xy-4
=2(x+y)+y-xy-4
=-8+2-4
=-10;

略
